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y^2-27y+70=0
a = 1; b = -27; c = +70;
Δ = b2-4ac
Δ = -272-4·1·70
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{449}}{2*1}=\frac{27-\sqrt{449}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{449}}{2*1}=\frac{27+\sqrt{449}}{2} $
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